tag:blogger.com,1999:blog-19785070.post116600711363004801..comments2015-02-15T01:38:30.207-07:00Comments on The Third Edge of the Sword: A small math problemFeynman and Coulter's Love Childhttp://www.blogger.com/profile/05129851946309441082noreply@blogger.comBlogger2125tag:blogger.com,1999:blog-19785070.post-1166029519382168742006-12-13T10:05:00.000-07:002006-12-13T10:05:00.000-07:00My stab at the integral:2/3(Ax^5/5 - Bx^4/4 + Cx^3...My stab at the integral:<BR/><BR/>2/3(Ax^5/5 - Bx^4/4 + Cx^3/3 -Dx^2/2)^3/2<BR/><BR/>I know its wrong, and virtually unreadable, but I'd like to know the answer!Nathan Giesbrechthttps://www.blogger.com/profile/09848136659314278243noreply@blogger.comtag:blogger.com,1999:blog-19785070.post-1166028440272751222006-12-13T09:47:00.000-07:002006-12-13T09:47:00.000-07:00In step 5 when you divide both sides by (x-y) you ...In step 5 when you divide both sides by (x-y) you are, in fact, dividing by zero.<BR/><BR/>Now maybe it's time for me to look at that integral...Nathan Giesbrechthttps://www.blogger.com/profile/09848136659314278243noreply@blogger.com